| Author | Message | ||
     Krt9r |
Hi there, My '03 XB9R is killing one speedo sensor after the other. I have read about Reepicheep filters but as I have access to all needed tools at work I fancy doing my own rewire kit. I found on here the instruction sheets of the Buell kit, but a couple of things remain unclear: Is the resistor wire really needed? If so does anyone know how many Ohms are needed, and where the "ring terminal" is supposed to be connected (could not find this in the instructions)? By the way, the instruction sheets I have are of quite poor resolution, so if anyone can provide me with a higher res version that would be great! Cheers,  Olivier | ||
| U4euh |
I bought a sensor for an 06 sportster, came with a longer wire, but otherwise fit perfect. That was 17,000 miles ago! Just a thought. | ||
| Reepicheep |
If you are going DIY anyway, just put a 5v regulator inline with the new filter (downstream of the connector). Go to the junk drawer, and grab an old cell phone car adapter. Wire it into that. When you take them apart and cut them down, they usually get nice and small. I'll be happy to help you out if you need it as well, just don't tell anybody ;) I think you want a regulator, not a resistor. A resistor will just blow the sensor with less current. | ||
| Krt9r |
Thanks guys. Regarding the sensor I changed it already for the new uprated one and it failed within a few 1000miles...  Reepicheep I have what it takes at work to make a rewire kit as sold by Buell, except that I do not know the value of the resistor included in the "resistor wire" of the kit. I was just wondering whether someone on here happened to know about that value... I have already gathered all the info about your regulators thanks! Just have to decide which way to go really. Cheers, Olivier | ||
| Firewhirl |
i have the re-wire kit. sell it to you dirt cheap. | ||
| Firewhirl |
never mind. i viewed your profile and u live in Belgium | ||
| Krt9r |
Thanks anyway...  Could you measure the resistance of the resistor wire? | ||
| Reepicheep |
Is it just one part in series with one wire? Or does it go in parallel (bridging) two wires, and have a third wire coming off it? If it's in series on one wire, it may be an inductor, not a resistor. That would be my best guess. In that case, get the biggest one you can comfortably package on the bike. 10 uH (10 micro henrys) or bigger will probably do the trick... though if were me and my $50 sensor, I would want a regulator on there. If it comes off an ecm supply of some sort, then perhaps it is a resistor, in which case it's only role is to keep from blowing something else up if you have a sensor that is already shorted to ground. If thats the case, try 250 or 500 ohms. | ||
| Krt9r |
If it comes off an ecm supply of some sort, then perhaps it is a resistor, in which case it's only role is to keep from blowing something else up if you have a sensor that is already shorted to ground. If thats the case, try 250 or 500 ohms. Yep this resistor wire has to be inserted between the original voltage source and the ground. I suspect it is indeed supposed to somehow replicate the current drawn by the original sensor. (What I can't work out though is why it's not needed for the X1, S3 and M2 models...  ) Thanks for the tip on the resistor values to try.  | ||
| Reepicheep |
Don't get that resistor yet... I scared up the scans of the pages and am trying to figure out what on earth they are using that resistor for. It's not what I was originally speculating when I calculated those values... | ||
| Krt9r |
Same here. I mean I have been running for some time with f$%&ed sensors so virtually as if nothing was connected there and did not notice anything strange... Anyway if you want to allow a few mA running through that wire you have to use ~500/1k ohms, I wanted to try and check my assumptions were right. | ||
| Reepicheep |
OK... I am guessing that for some reason that on the 9r they are pulling an ECM output voltage rather then the regulated ECM input. Don't know why, but they must have had a reason. So that resistor is probably just to put a load on the output so it flows enough current to regulate. I doubt the sensor (being a hall effect semiconductor) pulls much current at all. So try a 1k resistor. 500 ohms would probably be OK as well. | ||
| Reepicheep |
Ain't it great when simultaneous postings agree | ||
| Krt9r |
 |
